Optimal. Leaf size=261 \[ \frac{\sqrt{c+d \tan (e+f x)} (a+b \tan (e+f x))^{m+1} F_1\left (m+1;-\frac{1}{2},1;m+2;-\frac{d (a+b \tan (e+f x))}{b c-a d},\frac{a+b \tan (e+f x)}{a-i b}\right )}{2 f (m+1) (b+i a) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}}-\frac{\sqrt{c+d \tan (e+f x)} (a+b \tan (e+f x))^{m+1} F_1\left (m+1;-\frac{1}{2},1;m+2;-\frac{d (a+b \tan (e+f x))}{b c-a d},\frac{a+b \tan (e+f x)}{a+i b}\right )}{2 f (m+1) (-b+i a) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}} \]
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Rubi [A] time = 0.283494, antiderivative size = 261, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {3575, 912, 137, 136} \[ \frac{\sqrt{c+d \tan (e+f x)} (a+b \tan (e+f x))^{m+1} F_1\left (m+1;-\frac{1}{2},1;m+2;-\frac{d (a+b \tan (e+f x))}{b c-a d},\frac{a+b \tan (e+f x)}{a-i b}\right )}{2 f (m+1) (b+i a) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}}-\frac{\sqrt{c+d \tan (e+f x)} (a+b \tan (e+f x))^{m+1} F_1\left (m+1;-\frac{1}{2},1;m+2;-\frac{d (a+b \tan (e+f x))}{b c-a d},\frac{a+b \tan (e+f x)}{a+i b}\right )}{2 f (m+1) (-b+i a) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}} \]
Antiderivative was successfully verified.
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Rule 3575
Rule 912
Rule 137
Rule 136
Rubi steps
\begin{align*} \int (a+b \tan (e+f x))^m \sqrt{c+d \tan (e+f x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{(a+b x)^m \sqrt{c+d x}}{1+x^2} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{\operatorname{Subst}\left (\int \left (\frac{i (a+b x)^m \sqrt{c+d x}}{2 (i-x)}+\frac{i (a+b x)^m \sqrt{c+d x}}{2 (i+x)}\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{i \operatorname{Subst}\left (\int \frac{(a+b x)^m \sqrt{c+d x}}{i-x} \, dx,x,\tan (e+f x)\right )}{2 f}+\frac{i \operatorname{Subst}\left (\int \frac{(a+b x)^m \sqrt{c+d x}}{i+x} \, dx,x,\tan (e+f x)\right )}{2 f}\\ &=\frac{\left (i \sqrt{c+d \tan (e+f x)}\right ) \operatorname{Subst}\left (\int \frac{(a+b x)^m \sqrt{\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}}}{i-x} \, dx,x,\tan (e+f x)\right )}{2 f \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}}+\frac{\left (i \sqrt{c+d \tan (e+f x)}\right ) \operatorname{Subst}\left (\int \frac{(a+b x)^m \sqrt{\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}}}{i+x} \, dx,x,\tan (e+f x)\right )}{2 f \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}}\\ &=\frac{F_1\left (1+m;-\frac{1}{2},1;2+m;-\frac{d (a+b \tan (e+f x))}{b c-a d},\frac{a+b \tan (e+f x)}{a-i b}\right ) (a+b \tan (e+f x))^{1+m} \sqrt{c+d \tan (e+f x)}}{2 (i a+b) f (1+m) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}}-\frac{F_1\left (1+m;-\frac{1}{2},1;2+m;-\frac{d (a+b \tan (e+f x))}{b c-a d},\frac{a+b \tan (e+f x)}{a+i b}\right ) (a+b \tan (e+f x))^{1+m} \sqrt{c+d \tan (e+f x)}}{2 (i a-b) f (1+m) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}}}\\ \end{align*}
Mathematica [F] time = 0.663916, size = 0, normalized size = 0. \[ \int (a+b \tan (e+f x))^m \sqrt{c+d \tan (e+f x)} \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.386, size = 0, normalized size = 0. \begin{align*} \int \sqrt{c+d\tan \left ( fx+e \right ) } \left ( a+b\tan \left ( fx+e \right ) \right ) ^{m}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \tan \left (f x + e\right ) + c}{\left (b \tan \left (f x + e\right ) + a\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{d \tan \left (f x + e\right ) + c}{\left (b \tan \left (f x + e\right ) + a\right )}^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \tan{\left (e + f x \right )}\right )^{m} \sqrt{c + d \tan{\left (e + f x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \tan \left (f x + e\right ) + c}{\left (b \tan \left (f x + e\right ) + a\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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